Taking a very simple example of looping over a sentence and creating a dictionary which maps {x:y}
, where x
is a key representing the length of the words and y
is a list of words in the sentence that contain x
amount of letters
Input:
mywords = "May your coffee be strong and your Monday be short"
Expected Output:
{2: ['be', 'be'], 3: ['May', 'and'], 4: ['your', 'your'], 5: ['short'], 6: ['coffee', 'strong', 'Monday']}
Here's an attempt that creates a list of values but overwrites it each time:
{len(x):[x] for x in mywords.split()}
{2: ['be'], 3: ['and'], 4: ['your'], 5: ['short'], 6: ['Monday']}
Is it possible to do this in one line in Python?
Best Answer
Sure, you can, using
sorted
+groupby
, but it doesn't look great.P.S., Here's my answer (using
defaultdict
that I recommend over this) to the original question.