Python Random – Generate Random Numbers with Specific Digits

You can use either of random.randint or random.randrange. So to get a random 3-digit number:

from random import randint, randrange

randint(100, 999)     # randint is inclusive at both ends
randrange(100, 1000)  # randrange is exclusive at the stop

^{* Assuming you really meant three digits, rather than "up to three digits".}

To use an arbitrary number of digits:

from random import randint

def random_with_N_digits(n):
    range_start = 10**(n-1)
    range_end = (10**n)-1
    return randint(range_start, range_end)
    
print random_with_N_digits(2)
print random_with_N_digits(3)
print random_with_N_digits(4)

Output:

33
124
5127

Use random.choice on a list, but first remove that particular number from the list:

>>> import random
>>> n = 3
>>> end  = 5
>>> r = list(range(1,n)) + list(range(n+1, end))
>>> r
[1, 2, 4]
>>> random.choice(r)
2
>>> random.choice(r)
4

Or define a function:

def func(n, end, start = 1):
    return list(range(start, n)) + list(range(n+1, end))
... 
>>> r = func(3, 5)
>>> r
[1, 2, 4]
>>> random.choice(r)
2

Update:

This returns all numbers other than a particular number from the list:

>>> r = range(5)
for player in r:
    others = list(range(0, player)) + list(range(player+1, 5))
    print player,'-->', others
...     
0 --> [1, 2, 3, 4]
1 --> [0, 2, 3, 4]
2 --> [0, 1, 3, 4]
3 --> [0, 1, 2, 4]
4 --> [0, 1, 2, 3]