Python – Get Fully Qualified Class Name of an Object

pythonpython-datamodel

For logging purposes I want to retrieve the fully qualified class name of a Python object. (With fully qualified I mean the class name including the package and module name.)

I know about x.__class__.__name__, but is there a simple method to get the package and module?

Best Answer

With the following program

#!/usr/bin/env python

import foo

def fullname(o):
    klass = o.__class__
    module = klass.__module__
    if module == 'builtins':
        return klass.__qualname__ # avoid outputs like 'builtins.str'
    return module + '.' + klass.__qualname__

bar = foo.Bar()
print(fullname(bar))

and Bar defined as

class Bar(object):
  def __init__(self, v=42):
    self.val = v

the output is

$ ./prog.py
foo.Bar

If you're still stuck on Python 2, you'll have to use __name__ instead of __qualname__, which is less informative for nested classes - a class Bar nested in a class Foo will show up as Bar instead of Foo.Bar:

def fullname(o):
    klass = o.__class__
    module = klass.__module__
    if module == '__builtin__':
        return klass.__name__ # avoid outputs like '__builtin__.str'
    return module + '.' + klass.__name__
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