Python Path – How to Get Filename Without Extension

pathpythonstring

How do I get the filename without the extension from a path in Python?

"/path/to/some/file.txt"  →  "file"

Best Answer

Python 3.4+

Use pathlib.Path.stem

>>> from pathlib import Path
>>> Path("/path/to/file.txt").stem
'file'
>>> Path("/path/to/file.tar.gz").stem
'file.tar'

Python < 3.4

Use os.path.splitext in combination with os.path.basename:

>>> os.path.splitext(os.path.basename("/path/to/file.txt"))[0]
'file'
>>> os.path.splitext(os.path.basename("/path/to/file.tar.gz"))[0]
'file.tar'

Related Solutions

Python – Extract File Name from Path Across OS Formats

There's a function that returns exactly what you want

import os
print(os.path.basename(your_path))

WARNING: When os.path.basename() is used on a POSIX system to get the base name from a Windows-styled path (e.g. "C:\\my\\file.txt"), the entire path will be returned.

Example below from interactive python shell running on a Linux host:

Python 3.8.2 (default, Mar 13 2020, 10:14:16)
[GCC 9.3.0] on Linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import os
>>> filepath = "C:\\my\\path\\to\\file.txt" # A Windows style file path.
>>> os.path.basename(filepath)
'C:\\my\\path\\to\\file.txt'

Python – How to Extract File Name from File Path

If all you want to do is truncate the file paths to just the filename, you can use os.path.basename:

for file in files:
    fname = os.path.basename(file)
    dict_[fname] = (pd.read_csv(file, header=0, dtype=str, encoding='cp1252')
                      .fillna(''))

Example:

os.path.basename('Desktop/test.txt')
# 'test.txt'