C – How to Initialize an Array Without a Loop

c++

Lets say I have an array like

int arr[10][10];

Now i want to initialize all elements of this array to 0. How can I do this without loops or specifying each element?

Please note that this question if for C

Best Answer

The quick-n-dirty solution:

int arr[10][10] = { 0 };

If you initialise any element of the array, C will default-initialise any element that you don't explicitly specify. So the above code initialises the first element to zero, and C sets all the other elements to zero.

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C – How to Dynamically Initialize Array with Default Value

You can use void *calloc(size_t nmemb, size_t size); function to initialize memory with 0,

The calloc() function allocates memory for an array of nmemb elements of size bytes each and returns a pointer to the allocated memory. The memory is set to zero. If nmemb or size is 0, then calloc() returns either NULL, or a unique pointer value that can later be successfully passed to free().

 calloc(number of elements, sizeof(type));

or you can also use memset() explicitly to initialize memory allocated by malloc() call.

Note: calloc() isn't magic either - it will also use a loop somewhere to replace the garbage with all zeroes.

Best Answer

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C – How to Dynamically Initialize Array with Default Value

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