Generating Random Number 0 or 1 in C#

c++random

Am I looking too far to see something as simple as pick a number: 0 or 1?

        Random rand = new Random();

        if (rand.NextDouble() == 0)
        {
            lnkEvents.CssClass = "selected";
        }
        else
        {
            lnkNews.CssClass = "selected";
        }

Best Answer

Random rand = new Random();

if (rand.Next(0, 2) == 0)
    lnkEvents.CssClass = "selected";
else
    lnkNews.CssClass = "selected";

Random.Next picks a random integer between the lower bound (inclusive) and the upper bound (exclusive).

Related Solutions

C# – Generate Random Numbers

First, you shouldn't be newing up a random number generator every time you want a new random number. You should set the generator as a static or member variable and refer to it for each new number.

Second, you have to pass a min and a max to your RandomNumber method.

C# – How to Generate Random Number Between 0 and 1

According to the documentation, Next returns an integer random number between the (inclusive) minimum and the (exclusive) maximum:

Return Value

A 32-bit signed integer greater than or equal to minValue and less than maxValue; that is, the range of return values includes minValue but not maxValue. If minValue equals maxValue, minValue is returned.

The only integer number which fulfills

0 <= x < 1

is 0, hence you always get the value 0. In other words, 0 is the only integer that is within the half-closed interval [0, 1).

So, if you are actually interested in the integer values 0 or 1, then use 2 as upper bound:

var n = random.Next(0, 2);

If instead you want to get a decimal between 0 and 1, try:

var n = random.NextDouble();

Best Answer

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C# – Generate Random Numbers

C# – How to Generate Random Number Between 0 and 1

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