JavaScript – Why ‘if(“string”)’ Evaluates as True but ‘if(“string”==true)’ Does Not

javascript

Given the following code:

if ("string") {
    console.log('true!');
}
//logs "true" to the console
if ("string"==true) {
    console.log('true!');
}
//doesn't log anything

Why does this happen? I thought "string" was being cast to a number, as is the boolean. So true becomes 1, and "string" becomes NaN. The second if statement makes sense, but I don't see why the first statement causes the inner loop to be evaluated. What's going on here?

Best Answer

It is being cast to Boolean. Any non-empty string evaluates to true.

From the ECMAScript Language Specification:

12.5 The if statement

Semantics

The production IfStatement: if ( Expression ) Statement else Statement is evaluated as follows:

  1. Let exprRef be the result of evaluating Expression.
  2. If ToBoolean(GetValue(exprRef)) is true, then
    • Return the result of evaluating the first Statement.
  3. Else,
    • Return the result of evaluating the second Statement.

9.2 ToBoolean

The abstract operation ToBoolean converts its argument to a value of type Boolean according to Table 11:

Table 11 - ToBoolean Conversions

Undefined: false
Null: false
Boolean: The result equals the input argument (no conversion).
Number: The result is false if the argument is +0, -0, or NaN; otherwise the result is true.
String: The result is false if the argument is the empty String (its length is zero); otherwise the result is true.
Object: true

As far as the == operator is concerned, it's complicated, but the gist of it is that if you compare a number to a non-number the latter is converted into a number. If you compare a boolean against a non-boolean, the boolean is first converted to a number, and then the previous sentence applies.

See section 11.9.3 for details.

// Call this x == y.
if ("string" == true) 

// Rule 6: If Type(y) is Boolean,
//         return the result of the comparison x == ToNumber(y).
if ("string" == Number(true))

// Rule 5: If Type(x) is String and Type(y) is Number,
//         return the result of the comparison ToNumber(x) == y.  
if (Number("string") == Number(true))

// The above is equivalent to:
if (NaN == 1)

// And NaN compared to *anything* is false, so the end result is:
if (false)
Related Question