Python – How to Write Multiple Try Statements in One Block

exceptionpython

I want to do:

try:
    do()
except:
    do2()
except:
    do3()
except:
    do4()

If do() fails, execute do2(), if do2() fails too, exceute do3() and so on.

best Regards

Best Answer

If you really don't care about the exceptions, you could loop over cases until you succeed:

for fn in (do, do2, do3, do4):
    try:
        fn()
        break
    except:
        continue

This at least avoids having to indent once for every case. If the different functions need different arguments you can use functools.partial to 'prime' them before the loop.

Related Solutions

Python – Multiple Try Codes in One Block

You'll have to make this separate try blocks:

try:
    code a
except ExplicitException:
    pass

try:
    code b
except ExplicitException:
    try:
        code c
    except ExplicitException:
        try:
            code d
        except ExplicitException:
            pass

This assumes you want to run code c only if code b failed.

If you need to run code c regardless, you need to put the try blocks one after the other:

try:
    code a
except ExplicitException:
    pass

try:
    code b
except ExplicitException:
    pass

try:
    code c
except ExplicitException:
    pass

try:
    code d
except ExplicitException:
    pass

I'm using except ExplicitException here because it is never a good practice to blindly ignore all exceptions. You'll be ignoring MemoryError, KeyboardInterrupt and SystemExit as well otherwise, which you normally do not want to ignore or intercept without some kind of re-raise or conscious reason for handling those.

Best Answer

Related Solutions

Python – Multiple Try Codes in One Block

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